Honourable Bob, after 3 rounds

The Honourable Bob event got away to a good start with 32 contestants. Unfortunately Steven’s computer fell at the first hurdle, so Steven had to use high order calculus and other magic to determine the pairing for 2 weeks. But all has been restored to working order (apart from Steven’s mental capacity), and Julian and Cijo are on the maximum score after 3 rounds, with 2 rounds to play.

Round 3 results

  1 = McIntyre,Julian      ( 2.0) - Szuveges,Narelle S   ( 2.0) =  12 -   3 = 1 - 0
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  2 = Richards,Derek       ( 2.0) - Paul,Cijo            ( 2.0) =   9 -  14 = 0 - 1
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  3 = Humphreys,Scott      ( 1.5) - Beaumont,David       ( 1.5) =   5 -   1 = 0 - 1
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  4 = Davis,Tony J         ( 1.5) - Hogan,Steven         ( 1.5) =   2 -   7 = 1 - 0
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  5 = Enano,Ronald         ( 1.0) - Matijas,Dejan        ( 1.0) =   4 -  15 = 1 - 0
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  6 = Waadhwa,Ehsaas       ( 1.0) - Salanowski,Mark      ( 1.0) =  20 -   6 = 0 - 1
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  7 = Clerk,Max            ( 1.0) - Whitford,Matthew     ( 1.0) =  19 -   8 = 0 - 1
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  8 = Nowak,Ruben          ( 1.0) - Annapureddy,Dhruthin ( 1.0) =  10 -  18 = 1 - 0
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  9 = Nawar,Mena           ( 1.0) - McIntyre,Charlie     ( 1.0) =  22 -  13 = 0 - 1
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 10 = Zhang,Eric           ( 1.0) - Pethe,Abi            ( 0.5) =  30 -  31 = 0 - 1
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 11 = Saric,Sergey         ( 0.5) - Bejjanki,Pranav Sai  ( 0.5) =  11 -  23 = 1 - 0
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 12 = Waadhwa,Rakesh       ( 0.5) - Shelev,Petar         ( 0.5) =  28 -  17 = 0 - 1
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 13 = Brokies,Alwyn        ( 0.5) - Clerk,Felix          ( 0.5) =  32 -  21 = 0F-1F
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 14 = Zhang,Ben            ( 0.0) - Minic,Branislav      ( 0.0) =  29 -  24 = 1 - 0
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 15 = Deng,Tina            ( 0.0) - Watson,Nicolas       ( 0.5) =  27 -  25 = 0 - 1
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 16 = Condick,Peter        ( 0.0) - ( half point bye )   ( 0.0) =  26 -   0 = ½    
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 17 = McIntyre,Cameron     ( 0.5) - ( not paired )       ( 0.0) =  16 -   0 = 0

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